3m^2-13-56=0

Solution for 3m^2-13-56=0 equation:

3m^2-13-56=0

We add all the numbers together, and all the variables

3m^2-69=0

a = 3; b = 0; c = -69;
Δ = b2-4ac
Δ = 02-4·3·(-69)
Δ = 828
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{828}=\sqrt{36*23}=\sqrt{36}*\sqrt{23}=6\sqrt{23}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{23}}{2*3}=\frac{0-6\sqrt{23}}{6}
=-\frac{6\sqrt{23}}{6}
=-\sqrt{23}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{23}}{2*3}=\frac{0+6\sqrt{23}}{6}
=\frac{6\sqrt{23}}{6}
=\sqrt{23}
$